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calculus - What is infinity divided by infinity? - Mathematics Stack . . . Essentially, you gave the answer yourself: "infinity over infinity" is not defined just because it should be the result of limiting processes of different nature I e , since such a definition would be given for the sake of completeness and coherence with the fact "the limiting ratio is the ratio of the limits", your
One divided by Infinity? - Mathematics Stack Exchange $\begingroup$ Arithmetic with $\infty$ is usually a convention rather than a piece of mathematics (For example, some mathematicians (in measure theory) take $\infty\cdot 0 = 0$ and reason that this should be the case since $\infty\cdot 0$ represents the "area" of an infinite line in the plane with $0$ width and hence should be $0$ since area = height$\times$ width)
What is imaginary infinity, - Mathematics Stack Exchange The infinity can somehow branch in a peculiar way, but I will not go any deeper here This is just to show that you can consider far more exotic infinities if you want to Let us then turn to the complex plane The most common compactification is the one-point one (known as the Riemann sphere), where a single infinity $\tilde\infty$ is added
Types of infinity - Mathematics Stack Exchange $\begingroup$ "Or that the infinity of the even numbers is the same as that of the natural numbers " - not necessary This depends on your definitions I would argue the infinity of natural numbers is by 1 2 less than the infinity of even numbers (positive, negative and zero) I men, not 1 2 times, but the difference $\endgroup$ –
Is $0^\infty$ indeterminate? - Mathematics Stack Exchange (In the framework of the projectively extended real line, the limit is the unsigned infinity $\infty$ in all three cases )" $\endgroup$ – user236182 Commented Sep 16, 2017 at 23:50
calculus - Limits and infinity minus infinity - Mathematics Stack Exchange Infinity is not a number So there there is no general meaning to any "infinity arithmetic" expression Sometimes, though, there is a limit theorem which can be interpreted as an infinity arithmetic expression Here's one example of such a theorem:
Why is $\\infty\\times 0$ indeterminate? - Mathematics Stack Exchange Your title says something else than "infinity times zero" It says "infinity to the zeroth power" It is also an indefinite form because $$\infty^0 = \exp(0\log \infty) $$ but $\log\infty=\infty$, so the argument of the exponential is the indeterminate form "zero times infinity" discussed at the beginning
Is 1 + infinity - Mathematics Stack Exchange My argument is that if $1 + \infty > \infty$ then there exists a number greater than $\infty$, disproving the concept of infinity, because you can't simply add $1$ to infinity, because infinity is ever increasing So new_infinity would just become "1 + infinity"