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LAMBDA EMI INC

NEPTUNE-USA

Company Name:
Corporate Name:
LAMBDA EMI INC
Company Title: emipower.com - emipower Resources and Information. 
Company Description: emipower.com is your first and best source for information about emipower . here you will also find topics relating to issues of general interest. we hope you find what you are looking for! 
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Company Address: 405 Essex Road,NEPTUNE,NJ,USA 
ZIP Code:
Postal Code:
7753 
Telephone Number:  
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Website:
emipower. com 
Email:
 
USA SIC Code(Standard Industrial Classification Code):
792903 
USA SIC Description:
Music 
Number of Employees:
 
Sales Amount:
 
Credit History:
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Contact Person:
 
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Company News:
  • What exactly is lambda in Python? - Stack Overflow
    Also lambda can be used in an expression directly, while def is a statement def f(x, y): return x + y Would give you almost the same result as f = lambda x, y: x + y And you can use it directly in an expression g(5, 6, helper=lambda x, y: x + y) which with def would be less concise
  • Aggregating in pandas groupby using lambda functions
    Here is runnable example: import numpy as np import pandas as pd N = 100 data = pd DataFrame({ 'type': np random randint(10, size=N), 'status': np random randint(10
  • Is there a way to perform if in pythons lambda? [duplicate]
    @Glenn Maynard: There's almost no reason to use a lambda, period Assigning a lambda to a variable -- as a stand-in for def-- is generally a Very Bad Idea (tm) Just use a def so mere mortal programmers can read, interpret, understand and maintain it –
  • C# Lambda ( = gt; ) - Stack Overflow
    This is the lambda operator Which means 'goes to' It is used to create lambda expressions which is syntax offered by C# for anonymous methods eg lamda expression x=>x > 2 This mean that given x, x goes to x greater than 2 In other words this lambda expression will select x greater than 2 Anonymous method for the same can be written as
  • python - Lambda inside lambda - Stack Overflow
    p = lambda x: (lambda x: x%2)(x) 2 Note in Python 2 this example will always return 0 since the remainder from dividing by 2 will be either 0 or 1 and integer-dividing that result by 2 will result in a truncated 0




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