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LAMBDA METAL INC

POINTE-DU-LAC-Canada

Company Name:
Corporate Name:
LAMBDA METAL INC
Company Title:  
Company Description:  
Keywords to Search:  
Company Address: 1300 Ch Sainte-Marguerite,POINTE-DU-LAC,QC,Canada 
ZIP Code:
Postal Code:
G0X1Z0 
Telephone Number: 8193770508 
Fax Number: 8193770508 
Website:
 
Email:
 
USA SIC Code(Standard Industrial Classification Code):
359903 
USA SIC Description:
Machine Shops 
Number of Employees:
1 to 4 
Sales Amount:
$500,000 to $1 million 
Credit History:
Credit Report:
Good 
Contact Person:
Emile Blanchette 
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Company News:
  • What is a lambda expression, and when should I use one?
    Here is another really good reference which explains very well what are lambda expressions in C++: Microsoft com: Lambda expressions in C++ I especially like how well it explains the parts of a lambda expression, in particular: the capture clause, parameter list, trailing-return-type, and lambda body
  • Is there a way to perform if in pythons lambda? [duplicate]
    An easy way to perform an if in lambda is by using list comprehension You can't raise an exception in lambda, but this is a way in Python 3 x to do something close to your example:
  • python - List comprehension vs. lambda + filter - Stack Overflow
    by_attribute = lambda x: x attribute == value xs = filter(by_attribute , xs) Yes, that's two lines of code instead of one, but you clean filter expression from cumbersome lambda and by naming lambda nicely it literally becomes being read as "filter by attribute" :)
  • What is the difference between a closure and a lambda?
    The closure of a lambda expression is this particular set of symbols defined in the outer context (environment) that give values to the free symbols in this expression, making them non-free anymore It turns an open lambda expression, which still contains some "undefined" free symbols, into a closed one, which doesn't have any free symbols anymore
  • python - Syntax behind sorted (key=lambda: . . . ) - Stack Overflow
    I don't quite understand the syntax behind the sorted() argument: key=lambda variable: variable[0] Isn't lambda arbitrary? Why is variable stated twice in what looks like a dict?




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