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How to match, but not capture, part of a regex? - Stack Overflow The key observation here is that when you have either "apple" or "banana", you must also have the trailing hyphen, but you don't want to match it And when you're matching the blank string, you must not have the trailing hyphen A regex that encapsulates this assertion will be the right one, I think
If two cells match, return value from third - Stack Overflow =INDEX(B:B,MATCH(C2,A:A,0)) I should mention that MATCH checks the position at which the value can be found within A:A (given the 0, or FALSE, parameter, it looks only for an exact match and given its nature, only the first instance found) then INDEX returns the value at that position within B:B
. match () with a regular expression returns null - Stack Overflow For some reason, when using the match it always returns null Is there a way to fix this, or a better method to do this? Is there a way to fix this, or a better method to do this? Note: The code here is a snippet of much larger code, and in turn the value and type variable are usually defined by another method
How does the regular expression (aa)+\1 match aaaaaa? Again (aa)+ can match the remaining string So it matches the next aa Remaining string - "" Remember, the quantifiers by default act greedy They will match as much as they can Now, (aa)+ can't match any further Next in the pattern is \1 But there is nothing left to match Backtrack the last pattern matched by (aa)+ Remaining string - "aa"
How do if statements differ from match case statments in Python? This question asks for a switch case or match case equivalent in Python It seems since Python 3 10 we can now use match case statement I cannot see and understand the difference between match case and an if, elif statement other than the syntactical differences!
How can I compare two lists in python and return matches A quick performance test showing Lutz's solution is the best: import time def speed_test(func): def wrapper(*args, **kwargs): t1 = time time() for x in xrange(5000): results = func(*args, **kwargs) t2 = time time() print '%s took %0 3f ms' % (func func_name, (t2-t1)*1000 0) return results return wrapper @speed_test def compare_bitwise(x, y): set_x = frozenset(x) set_y = frozenset(y) return set
OR condition in Regex - Stack Overflow For example, ab|de would match either side of the expression However, for something like your case you might want to use the ? quantifier, which will match the previous expression exactly 0 or 1 times (1 times preferred; i e it's a "greedy" match) Another (probably more relyable) alternative would be using a custom character group:
regex - Match groups in Python - Stack Overflow Is there a way in Python to access match groups without explicitly creating a match object (or another way to beautify the example below)? Here is an example to clarify my motivation for the quest