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What is the norm of a complex number? [duplicate] In number theory, the "norm" is the determinant of this matrix In that sense, unlike in analysis, the norm can be thought of as an area rather than a length, because the determinant can be interpreted as an area (or volume in higher dimensions ) However, the area volume interpretation only gets you so far
Understanding L1 and L2 norms - Mathematics Stack Exchange I am not a mathematics student but somehow have to know about L1 and L2 norms I am looking for some appropriate sources to learn these things and know they work and what are their differences I am
What is the difference between the Frobenius norm and the 2-norm of a . . . For example, in matlab, norm (A,2) gives you induced 2-norm, which they simply call the 2-norm So in that sense, the answer to your question is that the (induced) matrix 2-norm is $\le$ than Frobenius norm, and the two are only equal when all of the matrix's eigenvalues have equal magnitude
2-norm vs operator norm - Mathematics Stack Exchange The operator norm is a matrix operator norm associated with a vector norm It is defined as $||A||_ {\text {OP}} = \text {sup}_ {x \neq 0} \frac {|A x|_n} {|x|}$ and different for each vector norm In case of the Euclidian norm $|x|_2$ the operator norm is equivalent to the 2-matrix norm (the maximum singular value, as you already stated) So every vector norm has an associated operator norm
The 1-Norm, the 2-Norm, and the Max-Norm - Mathematics Stack Exchange The unit circle, also the unit circle in the $\infty$ norm, which is a square; finally, the unit circle in the $1$ norm, which is a square rotated $45^\circ $ Anyway, get some graph paper and draw some pictures
matrices - Orthogonal matrix norm - Mathematics Stack Exchange The original question was asking about a matrix H and a matrix A, so presumably we are talking about the operator norm The selected answer doesn't parse with the definitions of A and H stated by the OP -- if A is a matrix or more generally an operator, (A,A) is not defined (unless you have actually defined an inner product on the space of