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Question #c548d - Socratic Question 1: K_ (sp)= 1 1 xx10^ (-11) Question 2: s= 4 9 xx10^ (-12)M Quest (1) determine the ksp for magnesium hydroxide Mg (OH)_2 where the molar solubility of Mg
Question #9f499 - Socratic Explanation: Your starting point here is the pH of the solution More specifically, you need to use the given pH to determine the concentration of hydroxide anions, #"OH"^ (-)#, present in the saturated solution
Calculating the concentration of excess HCL in E - Socratic The acid in excess is then titrated with N aOH (aq) of KNOWN concentration we can thus get back to the concentration or molar quantity of M (OH)2 as it stands the question (and answer) are hypothetical
Question #e7848 - Socratic Similarly, OH^- becomes H_2O, indicating a gain of a H^+ ion So, you can say that NH_4^+ is the acid, and OH^- is the base Conjugates are basically the "other" term For every acid, you have a conjugate base (that no longer has that extra H^+ ion), and for every base, you have a conjugate acid (that has an extra H^+ ion)
Question #370a7 - Socratic The sodium ions remain in solution as spectator ions If XS sodium hydroxide is added the precipitate redissolves to give the soluble plumbate (II) ion A simple way of writing this is: (chemguideUK) Ammonia solution can't do this as the concentration of OH^ (-) ions is not high enough
Question #750c8 - Socratic Here's what I got The problem wants you to use the base dissociation constant, K_b, of ammonia, "NH"_3, to determine the percent of ammonia molecules that ionize to produce ammonium cations, "NH"_4^(+), and hydroxide anions, "OH"^(-) As you know, ammonia is a weak base, which means that it does not ionize completely in aqueous solution Simply put, some molecules of ammonia will accept a
Question #71b91 - Socratic Since water is in excess, "67 7 g MgO" are needed to produce "98 0 g Mg(OH)"_2 Balanced equation "MgO(s) + H"_2"O(l)"rarr"Mg(OH)"_2("s")" Moles magnesium hydroxide Start with the given mass of "Mg(OH)"_2 and convert it to moles by dividing by its molar mass ("58 319 g mol") Since molar mass is a fraction, "g" "mol", we can divide by multiplying by the reciprocal of the molar mass, "mol" "g
Question #9be9c - Socratic The correct answer is a) hydroxide, carbonate, and hydrogen carbonate Alkalinity is another word for basicity (the concentration of hydroxide ions) a) Hydroxide ions OH⁻ are the strongest base you can have in water Carbonate ions and hydrogen carbonate ions also react with water to form hydroxide ions CO₃²⁻ + H₂O ⇌ HCO₃⁻ + OH⁻ HCO₃⁻ + H₂O ⇌ H₂CO₃ + OH⁻ b
Question #e1a77 - Socratic Answer is 286g (3s f) Concept required: mole calculation First start off by finding the number of moles for both compounds: PbCl (OH)=0 185 (207 2+35 5+16+1)*1000 (1kg=1000g) = 0 712 (to 3s f) Pb2Cl2CO3=0 185 (207 2*2+35 5*2+12+16*3)*1000 = 0 339 (to 3s f) Next, find the moles of Pb from each compound: Pb : PbCl (OH) 1 : 1 Therefore, moles of Pb in PbCl (OH) is 0 712 Pb : Pb2Cl2CO3 2 : 1