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Question #c548d - Socratic Question 1: K_ (sp)= 1 1 xx10^ (-11) Question 2: s= 4 9 xx10^ (-12)M Quest (1) determine the ksp for magnesium hydroxide Mg (OH)_2 where the molar solubility of Mg
Question #71ce2 - Socratic H^+ + OH^--> H_2O when the acid was added to the resulting solution The H^+ and OH^- react in a 1:1 ratio This tells us that the number of moles of H^+ used will be equal to the number of OH^- moles in solution Likewise, 2 moles of lithium produces 2 moles of OH^- This is also a 1:1 ratio
Question #6f539 + Example - Socratic The effect of strong base on water is to dramatically increase the concentration of OH^- ions and decrease the concentration of H_3O^+ ions Water always contains at least small concentrations of both OH^- (hydroxide) and H_3O^+ (hydronium) ions This is because water can react with itself in a self-ionization reaction: 2 H_2O harr H_3O^+ + OH^- At equilibrium, which is attained quickly for
Question #9f499 - Socratic Explanation: Your starting point here is the pH of the solution More specifically, you need to use the given pH to determine the concentration of hydroxide anions, #"OH"^ (-)#, present in the saturated solution
Question #645c9 - Socratic How about these? > (a) With "HCN" The "HCN" adds across the α "C=O" group to form a cyanohydrin underbrace ("CH"_3"COCOOH")_color (red) ("pyruvic acid") + "HCN" →
Question #e7848 - Socratic Similarly, OH^- becomes H_2O, indicating a gain of a H^+ ion So, you can say that NH_4^+ is the acid, and OH^- is the base Conjugates are basically the "other" term For every acid, you have a conjugate base (that no longer has that extra H^+ ion), and for every base, you have a conjugate acid (that has an extra H^+ ion)
Question #aea80 - Socratic Hydroxide is a polyatomic ion which has a -1 charge (#OH^_#) Hydroxide will pair with positively charged ions in ratios which will form an electrically neutral compound
Question #6b37a + Example - Socratic The longer the alkyl chain attached to the hydroxyl head, usually the more basic the conjugate base is (and the less nucleophilic)
Question #71b91 - Socratic Since water is in excess, "67 7 g MgO" are needed to produce "98 0 g Mg(OH)"_2 Balanced equation "MgO(s) + H"_2"O(l)"rarr"Mg(OH)"_2("s")" Moles magnesium hydroxide Start with the given mass of "Mg(OH)"_2 and convert it to moles by dividing by its molar mass ("58 319 g mol") Since molar mass is a fraction, "g" "mol", we can divide by multiplying by the reciprocal of the molar mass, "mol" "g
Question #750c8 - Socratic Here's what I got The problem wants you to use the base dissociation constant, K_b, of ammonia, "NH"_3, to determine the percent of ammonia molecules that ionize to produce ammonium cations, "NH"_4^(+), and hydroxide anions, "OH"^(-) As you know, ammonia is a weak base, which means that it does not ionize completely in aqueous solution Simply put, some molecules of ammonia will accept a