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Why sqrt(4) isnt equall to-2? - Mathematics Stack Exchange If you want the negative square root, that would be $-\sqrt {4} = -2$ Both $-2$ and $2$ are square roots of $4$, but the notation $\sqrt {4}$ corresponds to only the positive square root
What is the Taylor series of a square root? [duplicate] Here is the "smallest" representation I know of $$\sqrt {x+1} = \sum_ {n\ge 0} \dbinom {\tfrac {1} {2}} {n} x^n$$ This is not strictly a Taylor series It is actually the Binomial Expansion It is still an infinite series Is this what you are looking for? Edit: Actually, looking at the series you calculated, these two representations should be the same
radicals - Square root of a number squared is equal to the absolute . . . 5 You are referring to the principal square root From Wikipedia: "Although the principal square root of a positive number is only one of its two square roots, the designation 'the square root' is often used to refer to the principal square root "
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Isnt square root a bit like Log()? - Mathematics Stack Exchange I took a look at square root Squaring the number means x^2 And if I understood the square root correctly it does a bit inverse of squaring a number and gets back the x I had a friend tell me a while ago that Log() is also opposite of exponent, wouldn't that mean that square root is like a variant of Log () that only inverse a
The magic diagram is cartesian - Mathematics Stack Exchange Just rephrase using the functor of points or universal properties (this is admittedly a bit cumbersome) But you want to show that the square is cartesian Well again, I'm sure this can be done using universal properties arguments (or functor of points, probably more easily), but sometimes it can be easier to just get down to the dirty, so to