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%p Format specifier in c - Stack Overflow If this is what you are asking, %p and %Fp print out a pointer, specifically the address to which the pointer refers, and since it is printing out a part of your computer's architecture, it does so in Hexadecimal In C, you can cast between a pointer and an int, since a pointer is just a 32-bit or 64-bit number (depending on machine architecture) referring to the aforementioned chunk of memory
xml - Regular expression \p {L} and \p {N} - Stack Overflow 283 \p{L} matches a single code point in the category "letter" \p{N} matches any kind of numeric character in any script Source: regular-expressions info If you're going to work with regular expressions a lot, I'd suggest bookmarking that site, it's very useful
windows - What does p mean in set p? - Stack Overflow What does p stand for in set p=? I know that enables a switch, and I'm fairly sure that I know a is for arithmetic I've heard numerous rumours, some saying p is for prompt, others stating it
c++ - Where is `%p` useful with printf? - Stack Overflow %p will also use an adequate textural representation for pointer for the platform On platforms where it is common to represent pointer in hex, this won't make a difference as long as the size is correct but for a segmented architecture (do you remember DOS?) it may use a segment:offset representation
c - why is *pp [0] equal to **pp - Stack Overflow So pp [0] points to the address of p, which is 0x2000, and by dereferencing I would expect to get the contents of address 0x2000 That's were your reasoning strays, but understandably so In C, the right hand side of an assignment, or generally an evaluation of an lvalue (vulgo: variable), more precisely an lvalue-to-rvalue conversion, is already a dereferencing! For example, int i, j=0; i=j
unix - mkdirs -p option - Stack Overflow I'm confused about what the -p option does in Unix I used it for a lab assignment while creating a subdirectory and then another subdirectory within that one It looked like this: mkdir -p cmps012m lab1 This is in a private directory with normal rights (rlidwka) Oh, and would someone mind giving a little explanation of what rlidwka means?