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calculus - Why is antiderivative also known as primitive . . . While antiderivative, primitive, and indefinite integral are synonymous in the United States, other languages seem not to have any equivalent terms for antiderivative As others have pointed out here How common is the use of the term "primitive" to mean "antiderivative"?, some languages such as Dutch only use the term, primitive
elementary number theory - Find all the primitive roots of $13 . . . 2 Primes have not just one primitive root, but many So you find the first primitive root by taking any number, calculating its powers until the result is 1, and if p = 13 you must have 12 different powers until the result is 1 to have a primitive root
What are primitive roots modulo n? - Mathematics Stack Exchange The important fact is that the only numbers $n$ that have primitive roots modulo $n$ are of the form $2^\varepsilon p^m$, where $\varepsilon$ is either $0$ or $1$, $p$ is an odd prime, and $m\ge0$
Finding a primitive root of a prime number How would you find a primitive root of a prime number such as 761? How do you pick the primitive roots to test? Randomly? Thanks
Are all natural numbers (except 1 and 2) part of at least one primitive . . . Hence, all odd numbers are included in at least one primitive triplet Except 1, because I'm not allowing 0 to be a term in a triplet I can't think of any primitive triplets that have an even number as the hypotenuse, but I haven't been able to prove that none exist
What is a primitive root? - Mathematics Stack Exchange I have read that, but essentially what I want to know is, can a primitive root be defined in a simpler, easier to understand way? For my level of mathematics, some of the more formal definitions can be hard to understand sometimes
Show that $2$ is a primitive root modulo $13$. Hence $2$ has order $12$ modulo 13 and is therefore a primitive root modulo $13$ Now note all even powers of $2$ can't be primitive roots as they are squares modulo $13$ $ (*)$
The primitive $n^ {th}$ roots of unity form basis over $\mathbb {Q . . . We fix the primitive roots of unity of order $7,11,13$, and denote them by $$ \tag {*} \zeta_7,\zeta_ {11},\zeta_ {13}\ $$ Now we want to take each primitive root of prime order from above to some power, then multiply them When the number of primes is small, or at least fixed, the notations are simpler