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algorithm - Minimum number of operations to make an array non . . . The number of operations to make the entire sequence non-decreasing is equal to the number of elements in the input array minus the length of this subsequence Using binary search to determine where to place the next value, the worst case time complexity of this approach is O (n log n)
2702. Minimum Operations to Make Numbers Non-positive This detailed example walkthrough shows us how the binary search can efficiently find the minimum number of operations to reduce all array elements to zero or less
Minimum Operations to Make Numbers Non-positive This problem requires finding the minimum number of operations to make all elements in an array non-positive Each operation involves decrementing one element by x and all others by y
2702. Minimum Operations to Make Numbers Non-positive - Detailed . . . Given a 0-indexed array of positive integers nums and two positive integers x and y (with y < x), you can perform the following operation on the array: choose an index i and decreasenums [i] by x while decreasing every other element (all indices except i) by y
Minimum increments to make the array non-decreasing Approach: To solve the problem, follow the below idea: The problem can be solved using Dynamic Programming as at every index we have 2 choices to either apply the operation or don't apply the operation
2702 - Minimum Operations to Make Numbers Non-positive You are given a 0-indexed integer array nums and two integers x and y In one operation, you must choose an index i such that 0 <= i < nums length and perform the following: