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What does . shape [] do in for i in range (Y. shape [0])? shape is a tuple that gives you an indication of the number of dimensions in the array So in your case, since the index value of Y shape[0] is 0, your are working along the first dimension of your array
arrays - what does numpy ndarray shape do? - Stack Overflow 82 yourarray shape or np shape() or np ma shape() returns the shape of your ndarray as a tuple; And you can get the (number of) dimensions of your array using yourarray ndim or np ndim() (i e it gives the n of the ndarray since all arrays in NumPy are just n-dimensional arrays (shortly called as ndarray s))
What does shape[0] and shape[1] do in python? - Stack Overflow In python shape [0] returns the dimension but in this code it is returning total number of set Please can someone tell me work of shape [0] and shape [1]? Code: m_train = train_set_x_orig shape [0]
I want to know what it means (height,width)=img. shape [:2] It depends on what type the 'img' object is What are you using? I'm assuming opencv ? Then the shape of the object holds a tuple (rows, columns, channels) (height,width)=img shape[:2] is an example of tuple unpacking, with it you extract the rows and columns values from the shape tuple
python - list object has no attribute shape - Stack Overflow list object in python does not have 'shape' attribute because 'shape' implies that all the columns (or rows) have equal length along certain dimension Let's say list variable a has following properties:
python - Numpy array dimensions - Stack Overflow A piece of advice: your "dimensions" are called the shape, in NumPy What NumPy calls the dimension is 2, in your case (ndim) It's useful to know the usual NumPy terminology: this makes reading the docs easier!