SUMMATION FINANCIALBusiness Directories,Company Directories

Company Name: Corporate Name:	SUMMATION FINANCIAL
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Company Address:	12006 Highway 17 #7,STURGEON FALLS,ON,Canada
ZIP Code: Postal Code:	P2B3K8
Telephone Number:	7057533166
Fax Number:	7057539910
Website:
Email:
USA SIC Code(Standard Industrial Classification Code):	628205
USA SIC Description:	Financial Planning Consultants
Number of Employees:	1 to 4
Sales Amount:	$1 to 2.5 million
Credit History: Credit Report:	Institution
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summation - The idea behind the sum of powers of 2 - Mathematics Stack . . .
I know that the sum of powers of $2$ is $2^{n+1}-1$, and I know the mathematical induction proof But does anyone know how $2^{n+1}-1$ comes up in the first place For example, sum of n numbers is
summation - Sum of Fibonacci numbers - Mathematics Stack Exchange
elementary-number-theory summation fibonacci-numbers See similar questions with these tags
summation - How to prove a formula for the sum of powers of $2$ by . . .
How do I prove this by induction? Prove that for every natural number n, $ 2^0 + 2^1 + + 2^n = 2^{n+1}-1$ Here is my attempt Base Case: let $ n = 0$ Then, $2^{0+1} - 1 = 1$ Which is true
summation - How to convert Sigma Notation to a regular formula . . .
$\\sum_{i=1}^n i$ is the same as $\\frac{n(n+1)}{2}$ Can someone explain how the sigma notation is converted to this? I'm trying to figure out if there's a way to convert $\\sum_{i=1}^n i+(x-1)$
summation - Sum of odd numbers always gives a perfect square . . .
Explore related questions elementary-number-theory summation See similar questions with these tags
summation - Intuition behind the formula for $\sum_ {i=1}^n i^ {2 . . .
What is interesting is that your formula is the closed form for a different summation, i e $\displaystyle \sum_ {i=0}^n \binom {i+1}2=\sum_ {i=0}^n \frac {i (i+1)}2=\frac {n (n+1) (n+2)}6=\binom {n+2}3$
summation - Notation: What does $\sum_ {i gt;j}$ mean? - Mathematics Stack . . .
More specifically, I do not understand the condition on the summation: $$\sum_ {i>j}$$ Does this actually mean sum over both i and j, using only values of i that satisfy i>j ?
summation - Sum of fourth powers in terms of sum of squares . . .
Question: Is it possible to show this, purely by manipulating the summand, and without first expressing the summation in closed form and then factoring the sum of squares?