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super () in Java - Stack Overflow super() is a special use of the super keyword where you call a parameterless parent constructor In general, the super keyword can be used to call overridden methods, access hidden fields or invoke a superclass's constructor
Understanding Python super() with __init__() methods Super simply guarantees we call the correct next class's method in the method resolution order, whereas the other way hard-codes the next method to be called, which makes cooperative multiple inheritance more difficult
How does Pythons super () work with multiple inheritance? In fact, multiple inheritance is the only case where super() is of any use I would not recommend using it with classes using linear inheritance, where it's just useless overhead
java - When do I use super ()? - Stack Overflow I'm currently learning about class inheritance in my Java course and I don't understand when to use the super() call? Edit: I found this example of code where super variable is used: class A {
super object has no attribute __sklearn_tags__ 'super' object has no attribute '__sklearn_tags__' This occurs when I invoke the fit method on the RandomizedSearchCV object I suspect it could be related to compatibility issues between Scikit-learn and XGBoost or Python version I am using Python 3 12, and both Scikit-learn and XGBoost are installed with their latest versions
What is the difference between super and extends in Java Generics Anyway, his question wasn't when to use super vs extends, but what they actually mean This implies he's looking for the mechanical difference between the two to gain understanding of the 'why' to use rather than the 'when' to use This answer is at best tangential, but I think it's, rather, completely irrelevant to the question
coding style - Using super in C++ - Stack Overflow As for chaining super::super, as I mentionned in the question, I have still to find an interesting use to that For now, I only see it as a hack, but it was worth mentioning, if only for the differences with Java (where you can't chain "super")
What is a difference between lt;? super E gt; and lt;? extends E gt;? The first (<? super E>) says that it's "some type which is an ancestor (superclass) of E"; the second (<? extends E>) says that it's "some type which is a subclass of E" (In both cases E itself is okay ) So the constructor uses the ? extends E form so it guarantees that when it fetches values from the collection, they will all be E or some subclass (i e it's compatible) The drainTo method
What does calling super () in a React constructor do? super() will call the constructor of its parent class This is required when you need to access some variables from the parent class In React, when you call super with props, React will make props available across the component through this props See example 2 below without super()