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Para que serve função super(); - Stack Overflow em Português A diretiva super, sem parênteses, permite ainda invocar métodos da classe que foi derivada através da seguinte syntax super metodo(); Isto é útil nos casos em que faças override (sobrescrevas) um método da classe pai e desejas invocar o método original
python - replace block within { { super () }} - Stack Overflow In the child template, I would like to include everything that was in the head block from the base (by calling {{ super()) }} and include some additional things, yet at the same time replace the title block within the super call
coding style - Using super in C++ - Stack Overflow As for chaining super::super, as I mentionned in the question, I have still to find an interesting use to that For now, I only see it as a hack, but it was worth mentioning, if only for the differences with Java (where you can't chain "super")
What is a difference between lt;? super E gt; and lt;? extends E gt;? The first (<? super E>) says that it's "some type which is an ancestor (superclass) of E"; the second (<? extends E>) says that it's "some type which is a subclass of E" (In both cases E itself is okay ) So the constructor uses the ? extends E form so it guarantees that when it fetches values from the collection, they will all be E or some subclass (i e it's compatible) The drainTo method
Understanding Python super() with __init__() methods super() lets you avoid referring to the base class explicitly, which can be nice But the main advantage comes with multiple inheritance, where all sorts of fun stuff can happen
How does Pythons super () work with multiple inheritance? In fact, multiple inheritance is the only case where super() is of any use I would not recommend using it with classes using linear inheritance, where it's just useless overhead
super () in Java - Stack Overflow super() is a special use of the super keyword where you call a parameterless parent constructor In general, the super keyword can be used to call overridden methods, access hidden fields or invoke a superclass's constructor