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Specifying start-in directory in schtasks command in windows In this case the tn argument is mandatory, so set it: \tn mytask Export the newly created task to XML using schtasks query tn mytask xml > mytask xml Open mytasks xml in your favorite editor You should see something like this (I've hidden the not interesting parts):
What does True positive, FP, TN, FN corresponds when you do NER (Named . . . A True Negative (TN) is, by definition, everything that is NOT "birth year" recognized as NOT "birth year" In the context, every token word different from "2000" identified as NOT "birth year" is a TN If you want more example, you can find them in the Supplementary Information of this paper I wrote at Section "Fine tuning and Evaluation Metrics"
Confusion matrix for values labeled as TP, TN, FP, FN I can aggregate these values into total number of TP, TN, FP, FN However, I would like to display a confusion matrix similar to the one generated by using the folowing:
How to find TP,TN, FP and FN values from 8x8 Confusion Matrix Thanks Walter for your comments Weka gives me TP rate for each of the class so is that the same value which comes from confusion matrix? that's what I want to know Second is I want to calculate those values by hand (if Weka give those values i don't mind) I am using Weka GUI for the same
telnetlib python example - Stack Overflow tn write('exit\n') btw, telnetnetlib can be tricky and things varies depending on your FTP server and environment setup you might be better off looking into something like pexpect to automate login and user interaction over telnet
Total number of TP, TN, FP FN do not sum up to total number of . . . TP+FP+TN+FN = 94135 1205 The total sum is now reduced further by 45574 Same is true for epochs lower down the order Shouldn't the total sum be the same? If not then why does it keep on decreasing? Part 3 Why are the values for TP, FP, FN, TN in both training and validation floating numbers? As per my understanding these should always be integer
Complexity of the recursion: T (n) = T (n-1) + T (n-2) + C If you were also interested in finding an explicit formula for T(n) this may help We know that T(1) = c and T(2) = 2c and T(n) = T(n-1) + T(n-2) + c So just write T(n) and start expanding T(n) = T(n-1) + T(n-2) + c T(n) = 2*T(n-2) + T(n-3) + 2c T(n) = 3*T(n-3) + 2*T(n-4) + 4c T(n) = 5*T(n-4) + 3*T(n-5) + 7c and so on You see the coefficients are Fibonacci numbers themselves! Call F(n) the
Using schtasks from the command line, what parameter will wake the . . . You can then re-import this file on another machine (see below), and Wake-To-Run will be set or, Via the command line, create a task with the basics set (action, time, etc) Then, export the XML, programatically add the WakeToRun node (via XSLT or search replace), then re-import this updated XML: schtasks exe create tn xml MyTask xml f