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Python : Fibonacci sequence using range(x,y,n) - Stack Overflow It is more interesting to get the Fibonacci numbers up until a certain condition is met instead of an arbitrary numerical cutoff For instance, the code below detects the first Fibonacci number after 1 that is a square using a while loop over list comprehensions:
Fibonacci sequence using list in PYTHON? - Stack Overflow 3 I have a problem about making a fibonacci sequence to a list, I'm just new to python someone help me please This is my code I know this is looking wrong or something because it says invalid syntax I don't know what to do about this really : ( This code works for a normal code without using a list!
while loop - Fibonacci Sequence using Python - Stack Overflow Hello I am trying to write a script that prompts the user for an integer number (n), then prints all the Fibonacci numbers that are less than or equal to the input, in that order EXAMPLE: Enter a
Fibonacci Sequence In Python (Most Efficient) - Stack Overflow Anyone know the most efficient way of displaying the first 100 numbers in the Fibonacci Sequence in Python please? Here is my current code: fib1,fib2,fib3= 0,0,1 while fib3 lt; 100: print
Recursive function in python for Fibonacci sequence The problem comes when your code gets to the recursive call of fibonacci(2) Inside this call, it will then call fibonacci(1) and fibonacci(0) In the fibonacci(1) call, it will hit the if n == 1 condition, and properly terminate with a return value of 1 But the fibonacci(0) call does not stop; it calls fibonacci(-1) and fibonacci(-2) And the negative numbers just keep growing from there
python - Efficient calculation of Fibonacci series - Stack Overflow To find the sum of the first n even-valued fibonacci numbers directly, put 3n + 2 in your favourite method to efficiently compute a single fibonacci number, decrement by one and divide by two (fib((3*n+2) - 1) 2))