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Fraction rules A B C vs B C A - Mathematics Stack Exchange I suspect you meant to write $$\frac {\left (\frac BC\right)}A=\frac {B} {CA}$$ which is correct and can be established by multiplying by $\frac CC$ The only clue in what you wrote is the size of the fraction bars and your top one is the largest in both cases It is hard to see that in my browser, but the strucure of your MathJax makes it clear
If $A∆B=A∆C$, then $B=C$ - Mathematics Stack Exchange Interesting bit of MathJax lore: $$\begin {align} \quad ∆C \\ \quad\mathbin {\Delta} C \\ A\mathbin {\Delta} C \\ A∆C \\ A \Delta C \end {align}$$ The use of ∆ rather than \Delta in MathJax code causes it to appear as if it had said \mathbin {\Delta} except when nothing precedes it, in which case the spacing is as if it had had something before it Three of the posted answers
Simplification of: AB + AC + BC in boolean algebra I am trying to understand the simplification of the boolean expression: AB + A'C + BC I know it simplifies to A'C + BC And I understand why, but I cannot figure out how to perform the simplific
$A- (B∩C)= (A−B)∪ (B−C)$ proof - Mathematics Stack Exchange If your mobile device renders that poorly, I suggest upgrading to one built within the last decade I'm only offered some advice on making your posts more readable If you prefer to have your posts ignored because it just isn't worth it to wade though that Go right ahead and continue as you have